Sin^2x-5cosx=5

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Solution for Sin^2x-5cosx=5 equation:


Simplifying
Sin2x + -5cosx = 5

Reorder the terms:
-5cosx + in2xS = 5

Solving
-5cosx + in2xS = 5

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1in2xS' to each side of the equation.
-5cosx + in2xS + -1in2xS = 5 + -1in2xS

Combine like terms: in2xS + -1in2xS = 0
-5cosx + 0 = 5 + -1in2xS
-5cosx = 5 + -1in2xS

Divide each side by '-5osx'.
c = -1o-1s-1x-1 + 0.2in2o-1s-1S

Simplifying
c = -1o-1s-1x-1 + 0.2in2o-1s-1S

Reorder the terms:
c = 0.2in2o-1s-1S + -1o-1s-1x-1

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